Graph y = x^2 + (q - 2)x + 55 with a slider for q, or graph the inequality (q - 2)^2 - 220 < 0 to visually find the largest integer upper bound.
16
Math
Difficulty: Hard
In the given equation, is an integer constant. The given equation has no real solutions. What is the largest possible value of ?

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Step-by-step mathematical derivation with KaTeX proofs
Move all terms to one side of the equation:
Alternative SAT test-taking techniques & secondary verification strategies
Rearrange the equation to standard form: r^2 + (q - 2)r + 55 = 0. For no real solutions, the discriminant must be strictly negative: b^2 - 4ac < 0. Thus, (q - 2)^2 - 4(1)(55) < 0, which gives (q - 2)^2 < 220. Taking the square root gives q - 2 < sqrt(220) ≈ 14.832, meaning q < 16.832. The largest integer is 16.
Define f(x) = x^2 + (q - 2)x + 55 with a slider for q constrained to integers. Starting at q = 17, notice the parabola crosses the x-axis (has 2 real roots). Slide down to q = 16, and the parabola lifts completely above the x-axis (no x-intercepts, meaning no real solutions).
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18(w - a)(w + 5) = 6(w + 5) In the given equation, a is a constant. The sum of the solutions to the equation is \frac{37}{3}. What is the value of a?
Data Set Q | Value | Frequency | | :---: | :---: | | a | 110 | | b | 30 | | c | 0 | Data Set R | Value | Frequency | | :---: | :---: | | a | 0 | | b | 3 | | c | 11 | Data sets Q and R are summarized in the tables shown, where a, b, and c are positive, consecutive integers and a < b < c. Which statement comparing the means of the data sets is true?
Group the linear terms:
Here:
A quadratic equation has no real solutions if and only if its discriminant :
Substitute the coefficients:
Take the square root of both sides:
Since and , we know:
To find the maximum possible value:
Since must be an integer:
(Double-check: For , (valid). For , (invalid).)
Final Answer: 16